IMC 1996 · Problem 1

Day 110 points3rd IMC · Plovdiv, Bulgaria

Statement

Let for j=0,,nj = 0, \dots, n, aj=a0+jda_j = a_0 + jd, where a0a_0, dd are fixed real numbers. Put

A=(a0a1a2ana1a0a1an1a2a1a0an2anan1an2a0).A = \begin{pmatrix} a_0 & a_1 & a_2 & \dots & a_n \\ a_1 & a_0 & a_1 & \dots & a_{n-1} \\ a_2 & a_1 & a_0 & \dots & a_{n-2} \\ \vdots & \vdots & \vdots & \ddots & \vdots \\ a_n & a_{n-1} & a_{n-2} & \dots & a_0 \end{pmatrix}.

Calculate det(A)\det(A), where det(A)\det(A) denotes the determinant of AA.

Official solution

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