IMC 1996 · Problem 5

Day 220 points3rd IMC · Plovdiv, Bulgaria

Statement

(i) Prove that

limx+n=1nx(n2+x)2=12.\lim_{x \to +\infty} \sum_{n=1}^{\infty} \frac{nx}{(n^2 + x)^2} = \frac{1}{2}.

(ii) Prove that there is a positive constant cc such that for every x[1,)x \in [1, \infty) we have

n=1nx(n2+x)212cx.\left| \sum_{n=1}^{\infty} \frac{nx}{(n^2 + x)^2} - \frac{1}{2} \right| \le \frac{c}{x}.

Official solution

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