IMC 1998 · Problem 2

Day 15 points5th IMC · Blagoevgrad, Bulgaria

Statement

Prove that the following proposition holds for n=3n = 3 (5 points) and n=5n = 5 (7 points), and does not hold for n=4n = 4 (8 points).

"For any permutation π1\pi_1 of {1,2,,n}\{1, 2, \dots, n\} different from the identity there is a permutation π2\pi_2 such that any permutation π\pi can be obtained from π1\pi_1 and π2\pi_2 using only compositions (for example, π=π1π1π2π1\pi = \pi_1 \circ \pi_1 \circ \pi_2 \circ \pi_1)."

Official solution

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