Find limt↗1(1−t)∑n=1∞tn1+tn\lim\limits_{t \nearrow 1} (1-t) \sum\limits_{n=1}^{\infty} \dfrac{t^n}{1 + t^n}t↗1lim(1−t)n=1∑∞1+tntn, where t↗1t \nearrow 1t↗1 means that ttt approaches 111 from below.
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