IMC 2001 · Problem 2

Day 28th IMC · Prague, Czech Republic

Statement

Let a0=2a_0 = \sqrt{2}, b0=2b_0 = 2, an+1=24an2a_{n+1} = \sqrt{2 - \sqrt{4 - a_n^2}}, bn+1=2bn2+4+bn2b_{n+1} = \dfrac{2b_n}{2 + \sqrt{4 + b_n^2}}.

a) Prove that the sequences (an)(a_n), (bn)(b_n) are decreasing and converge to 00.

b) Prove that the sequence (2nan)(2^n a_n) is increasing, the sequence (2nbn)(2^n b_n) is decreasing and that these two sequences converge to the same limit.

c) Prove that there is a positive constant CC such that for all nn the following inequality holds: 0<bnan<C8n0 < b_n - a_n < \dfrac{C}{8^n}.

Official solution

Hidden so you can work on the problem first.