IMC 2002 · Problem 5

Day 29th IMC · Warsaw, Poland

Statement

Let AA be an n×nn \times n matrix with complex entries and suppose that n>1n > 1. Prove that

AA=In    SGLn(C)such thatA=SS1.A\overline{A} = I_n \iff \exists S \in GL_n(\mathbb{C}) \quad \text{such that} \quad A = S\overline{S}^{-1}.

(If A=[aij]A = [a_{ij}] then A=[aij]\overline{A} = [\overline{a_{ij}}], where aij\overline{a_{ij}} is the complex conjugate of aija_{ij}; GLn(C)GL_n(\mathbb{C}) denotes the set of all n×nn \times n invertible matrices with complex entries, and InI_n is the identity matrix.)

Official solution

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