IMC 2014 · Problem 4

Day 121st IMC · Blagoevgrad, Bulgaria

Statement

Let n>6n > 6 be a perfect number, and let n=p1e1pkekn = p_1^{e_1} \cdots p_k^{e_k} be its prime factorisation with 1<p1<<pk1 < p_1 < \dots < p_k. Prove that e1e_1 is an even number.

A number nn is perfect if s(n)=2ns(n) = 2n, where s(n)s(n) is the sum of the divisors of nn.

Official solution

Hidden so you can work on the problem first.