IMC 2023 · Problem 8

Day 230th IMC · Blagoevgrad, Bulgaria

Statement

Let TT be a tree with nn vertices; that is, a connected simple graph on nn vertices that contains no cycle. For every pair u,vu, v of vertices, let d(u,v)d(u, v) denote the distance between uu and vv, that is, the number of edges in the shortest path in TT that connects uu with vv.

Consider the sums

W(T)={u,v}V(T)uvd(u,v)andH(T)={u,v}V(T)uv1d(u,v).W(T) = \sum_{\substack{\{u,v\} \subseteq V(T) \\ u \ne v}} d(u, v) \quad \text{and} \quad H(T) = \sum_{\substack{\{u,v\} \subseteq V(T) \\ u \ne v}} \frac{1}{d(u, v)}.

Prove that

W(T)H(T)(n1)3(n+2)4.W(T) \cdot H(T) \ge \frac{(n-1)^3(n+2)}{4}.

Official solution

Hidden so you can work on the problem first.

Proposed by Slobodan Filipovski, University of Primorska, Koper.