IMC 1996 · Problem 3

Day 215 points3rd IMC · Plovdiv, Bulgaria

Statement

Let GG be the subgroup of GL2(R)GL_2(\mathbb{R}), generated by AA and BB, where

A=[2001],B=[1101].A = \begin{bmatrix} 2 & 0 \\ 0 & 1 \end{bmatrix}, \quad B = \begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix}.

Let HH consist of those matrices (a11a12a21a22)\begin{pmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \end{pmatrix} in GG for which a11=a22=1a_{11} = a_{22} = 1.

(a) Show that HH is an abelian subgroup of GG.

(b) Show that HH is not finitely generated.

Remarks. GL2(R)GL_2(\mathbb{R}) denotes, as usual, the group (under matrix multiplication) of all 2×22 \times 2 invertible matrices with real entries (elements). Abelian means commutative. A group is finitely generated if there are a finite number of elements of the group such that every other element of the group can be obtained from these elements using the group operation.

Official solution

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