IMC 2004 · Problem 1

Day 220 points11th IMC · Skopje, Macedonia

Statement

Let AA be a real 4×24 \times 2 matrix and BB be a real 2×42 \times 4 matrix such that

AB=(1010010110100101).AB = \begin{pmatrix} 1 & 0 & -1 & 0 \\ 0 & 1 & 0 & -1 \\ -1 & 0 & 1 & 0 \\ 0 & -1 & 0 & 1 \end{pmatrix}.

Find BABA.

Official solution

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