IMC 2004 · Problem 6

Day 110 points11th IMC · Skopje, Macedonia

Statement

For every complex number z{0,1}z \notin \{0,1\} define

f(z):=(logz)4,f(z) := \sum (\log z)^{-4},

where the sum is over all branches of the complex logarithm.

a) Show that there are two polynomials PP and QQ such that f(z)=P(z)/Q(z)f(z) = P(z)/Q(z) for all zC{0,1}z \in \mathbb{C} \setminus \{0,1\}.

b) Show that for all zC{0,1}z \in \mathbb{C} \setminus \{0,1\}

f(z)=zz2+4z+16(z1)4.f(z) = z \frac{z^2 + 4z + 1}{6(z-1)^4}.

Official solution

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